Refer the figure given below. 1 and 2 are refractive indices of air and lens material. The height of image will be cm. [figure]
- 1
- 0.5
- 1.2
- 0.25
Answer
(1) 1
Solution
Light goes from air ( 1=1) into glass ( 2=1.54). Measure distances from P, positive along the incident light.
u=-40 cm, R=-20 cm (centre C is on the object side)
2v- 1u= 2- 1R
1.54v- 1-40= 0.54-20
1.54v=-0.027-0.025=-0.052
v=- 1.540.052 -29.6 cm (virtual image, on the object side)
Magnification: m= 1v 2u= 1 (-29.6)1.54 (-40) 0.48
hi=m ho=0.48 2 0.96 cm 1 cm (erect)
Answer: (1)